Discussion Forum

$\int_{0}^{2x} (\sin x+|\sin x|)dx$ is equal to 

Answer:

Explanation:

$\int_{0}^{2x} (\sin x+|\sin x|)dx$

= $\int_{0}^{\pi} (\sin x+\sin x)dx$+$\int_{\pi}^{2 \pi} (\sin x-\sin x)dx$

  =$2\int_{0}^{\pi} \sin x dx$+0=$2 \int_{0}^{\pi} \cos x dx$

 =    $-2(\cos \pi-\cos 0)=-2(-1-1)=4$