1) Equation of the chord of the hyperbola $25x^{2}-16y^{2}=400$ which is bisected at the point (6,2) is A) 6x-7y=418 B) 75x-16y=418 C) 25x-4y=400 D) none of these Answer: Option BExplanation:Given hyperbola is $25x^{2}-16y^{2}=400$ If (6,2) is the mid point of the chord , then equation of chord is $T=S_{1}$ $\Rightarrow$ $25(6x)-16(2y)=25(36)-16(4)$ $\Rightarrow$ $75x-16y=450-32$ $\Rightarrow$ $75x-16y=418$
