Discussion Forum

Equation of the chord of the hyperbola $25x^{2}-16y^{2}=400$ which is bisected at the point (6,2) is 

Answer:

Explanation:

Given hyperbola is $25x^{2}-16y^{2}=400$

 If (6,2) is the mid point of the chord , then equation of chord is $T=S_{1}$

 $\Rightarrow$       $25(6x)-16(2y)=25(36)-16(4)$

$\Rightarrow$    $75x-16y=450-32$

$\Rightarrow$      $75x-16y=418$