Answer:
Option C
Explanation:
$A=\begin{bmatrix}3 & 4 \\5 & 7 \end{bmatrix}$
|A|=21-20=1
$\therefore$ $A(adj A)=\begin{bmatrix}3 & 4 \\5 & 7 \end{bmatrix}\begin{bmatrix}7 & -4 \\-5 & 3 \end{bmatrix}$
=$\begin{bmatrix}1 & 0 \\0 & 1 \end{bmatrix}=1.\begin{bmatrix}1 & 0 \\0 & 1 \end{bmatrix}=|A|.1$