Discussion Forum

According to Bohr's theory , the angular momentum for an electron of 3rd orbit is 

Answer:

Explanation:

Angular momentum ,mvr

   =$\frac{nh}{2\pi}=\frac{3 \times h}{2\pi}=\frac{1.5 h}{\pi}$

  $=3h$   $[ \because h=\frac{h}{2\pi}]$