Discussion Forum

A gaseous mixture containing  He,$CH_{4}$ and $SO_{2}$ was allowed to effuse through a fine hole then find what molar ratio of gases coming out initially ?(Given mixture contains $He,CH_{4}$ and  $SO_{2}$ in 1:2:3 mole ratio)

Answer:

Explanation:

$\frac{n'He}{n'CH_{4}}=\frac{1}{2}\sqrt{\frac{16}{4}}=\frac{1}{1}$

$\frac{n'He}{n'SO_{2}}=\frac{1}{3}\sqrt{\frac{64}{4}}=\frac{4}{3}$

So, molar ratio will be 

$n'He:n'CH_{4}:n'SO_{2}=4:4:3$