Chemistry | VITEEE 2014 | Discussion Page

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The bond angles of $NH_{3},NH_{4}^{+}$ and $NH_{2}^{-}$ are in the order

$NH_{2}^{-}$ >

$NH_{3}$ >

$NH_{4}^{-}$

$NH_{4}^{+}$ >

$NH_{3}$ >

$NH_{2}^{-}$

$NH_{3}$ >

$NH_{2}^{-}$ >

$NH_{4}^{-}$

D) NH >

$NH_{4}^{-}$ >

$NH_{2}^{-}$

Option B

On increases the number of lone pairs of electrons , bond angle decreases . therefore , order of bond angle is

$NH_{4}^{+}$ > $NH_{3}$ > $NH_{2}^{-}$

(no/p) (one/p) (two/p)

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