Discussion Forum



1)

The equivaent conductivity of a solution containing 2.54 g of CuSO4 per L is 91.0 W−1cm2eq−1 . Its conductivity would be 


A) 2.9×10−3Ω−1cm−1

B) 1.8×10−2Ω−1cm−1

C) 2.4×10−4Ω−1cm−1

D) 3.6×10−3Ω−1cm−1

Answer:

Option A

Explanation:

We know that,

  k=∧eq.C

Given,  ∧eq=91.0Ω−1cm2eq−1

k=(91Ω−1cm2eq−1)

                                           (2.54159/2×1000eq.cm−3)

 =2.9×10−3Ω−1cm−1