Chemistry | VITEEE 2014 | Discussion Page

The solubility product of $Ag_{2}CrO_{4}$ is $32 \times 10^{-12}$ . What is the concentration of $CrO_{4}^{-}$ ions in that solution?

$2 \times 10^{-4}M$

$1.6 \times 10^{-4}M$

$8 \times 10^{-4}M$

$7 \times 10^{-8}M$

Option A

$Ag_{2}CrO_{4} \rightarrow 2Ag^{+}+CrO_{4}^{2-}$

S 2S S

$K_{SP}=(2s)^{2}s=4s^{2}s=4s^{3}$

$S=\left(\frac{K_{sp}}{4}\right)^{1/3}\Rightarrow\left(\frac{32\times10^{-12}}{4}\right)^{1/3}=2\times10^{-4}M$

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