Discussion Forum

19.85mL of 0.01NaOH reacts with 20mL  of  HCl solution for complete neutralisation. the molarity of HCl solution is 

Answer:

Explanation:

Molarity of base= $\frac{normality}{acidity}=\frac{0.1}{1}=0.1$

 $M_{1}V_{1}=M_{2}V_{2}$

$0.1 \times 19.85=M_{2} \times20$

$M_{2}=0.09925  \approx 0.099$