1) 19.85mL of 0.01NaOH reacts with 20mL of HCl solution for complete neutralisation. the molarity of HCl solution is A) 9.9 B) 0.99 C) 0.099 D) 0.0099 Answer: Option CExplanation:Molarity of base= $\frac{normality}{acidity}=\frac{0.1}{1}=0.1$ $M_{1}V_{1}=M_{2}V_{2}$ $0.1 \times 19.85=M_{2} \times20$ $M_{2}=0.09925 \approx 0.099$
