1) A metal has bcc structure and the edge length of its unit cell is 3.04Å .The volume of the unit cell in $cm^{3}$ will be A) $1.6 \times10^{21}cm^{3}$ B) $2.81 \times10^{-23}cm^{3}$ C) $6.02 \times10^{-23}cm^{3}$ D) $6.6 \times10^{-24}cm^{3}$ Answer: Option BExplanation:Volume of unit cell (V)=$a^{3}$ $\therefore$ =$(3.04 \times 10^{-8}cm)^{3}$ =$2.81 \times 10^{-23} cm^{3}$
