Chemistry | VITEEE 2014 | Discussion Page

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A metal has bcc structure and the edge length of its unit cell is 3.04Å .The volume of the unit cell in $cm^{3}$ will be

$1.6 \times10^{21}cm^{3}$

$2.81 \times10^{-23}cm^{3}$

$6.02 \times10^{-23}cm^{3}$

$6.6 \times10^{-24}cm^{3}$

Option B

Volume of unit cell (V)= $a^{3}$

$\therefore$ = $(3.04 \times 10^{-8}cm)^{3}$

= $2.81 \times 10^{-23} cm^{3}$

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