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1)

MnO4+8H++5eMn2++4H2O;

E0=1.51V

MnO2+4H++2eMn2++2H2O;

E0=1.23VE0MnO4|MnO2 is 


A) 1.70 V

B) 0.91 V

C) 1.37 V

D) 0.548V

Answer:

Option A

Explanation:

 On subtracting  eqn.(ii) from (i)  we get

 MnO4+4H++3eMnO2+2H2O

    E3=1.51×5+2×1.233

                    E3=1.70V