Answer:
Option D
Explanation:
Given, frequency of carrier signal , f=5 MHz and peak voltage , $V_{c}$= 40V
Modulation index , $\mu$ =0.75
$\therefore$ $\mu=\frac{V_{m}}{V_{c}}$ [$\because V_{m}$ is peak voltage of message signal]
$0.75 =\frac{V_{m}}{40}$
$\Rightarrow$ $V_{m}=40 \times 0.75$
$V_{m}=30V$
Since, a difference of frequencies of two sidebands is equal to the bandwidth (2 fm).
i.e, Band width =40 kHz
$2f_{m}=40kHz \Rightarrow f_{m}=20kHz$
Hence, the peak voltage and frequency will be 30V and 20 kHz
