Answer:
Option A
Explanation:
Given , limit of resolution , $\alpha= 2.5 \times 10^{-7}$ rad
and wavelength , $\lambda$=500 nm
As, limit of resolution of a telescope,
$\alpha = \frac{1.22 \lambda}{a}$
So, $a= \frac{1.22 \lambda}{\alpha}= \frac{ 1.22 \times 500 \times 10^{-9}}{ 2.5 \times 10^{-7}}$
$\Rightarrow$ a=2.44 m
= 244 cm
Hence , the correct option is (a)