1)

The collision of an electron with kinetic energy  5.5 eV and a hydrogen atom in its ground  state can be described as


A) completely inelastic

B) may be completely inelastic

C) may be partially elastic

D) elastic

Answer:

Option D

Explanation:

Given, kinetic energy of electron =5.5 eV

The energy required to excite a hydrogen atom  from ground state (n=1) to first excited state (n=2) is 

$\triangle E= E_{2}-E_{1}$ 

=  -3.4-(-13.6)=10.2 eV

 When an electron collids with hydrogen atom in the ground state with energy of 5.5 eV which is less than 10.2 eV , then it will not be able to excite  hydrogen atom into first excited  state. Therefore, electron will not give any energy to the hydrogen atom. Gence , the total kinetic energy  of electron remains conserved . Hence , its collision with hydrogen  atom is elastic