Discussion Forum



1)

 An  inductor coil is connected to a capacitor  and an AC source of rms voltage 8V in series . The rms current in the circuit is 16 A and is in phase with emf . If this inductor coil is  connected to 6 V  DC battery, the magnitude of steady current is 


A) 8 A

B) 10 A

C) 12 A

D) 16 A

Answer:

Option C

Explanation:

Given , 

Rms voltage  of AC source $ V_{rms}=8V$   and the rms current  in the circuit , $I_{rms}=16 A$

 According to the question ,

672021161_a2.PNG

$\therefore$ impedance of the circuit

 $Z= \frac{V_{rms}}{I_{rms}}=\frac{8}{16}$

 Z=0.5 $\Omega$

 When the inductor coil is  is connected to a 6 V DC battery  then $V_{rms}$'=6 V= $V_{DC}$

$\therefore$   Magnitude of steady current,

 $I'=\frac{V'_{rms}}{Z}=\frac{6}{0.5}=12 A$