Answer:
Option C
Explanation:
Given, the percentage change in volume =0.4%
The change in volume of water is given by
$\triangle V= -\frac{p.V}{B}$
where , p= pressure applied on the sample of the matter.
Given,
$\frac{ \triangle V}{V}$= -0.4%= $\frac{0.4}{100}$
Pressure required , p= $B\left(-\frac{\triangle V}{V}\right)$
$=\frac{0.4}{100} \times 2\times 10^{9} P_a= \frac{0.4}{100}\times\frac{2\times 10^{9}}{101325}atm=79 atm\approx 80 atm$
Hence, 80 atm pressure is needed to compress a sample of water by 0.4%
