Discussion Forum

  The domain of the function 

$f(x)= \frac{1}{\sqrt{[x]^{2}-[x]^{}-2}}$  is 

 Here [x]  denotes the greatest integer not exceeding the value of [x]

Answer:

Explanation:

We have, 

$f(x)= \frac{1}{\sqrt{[x]^{2}-[x]^{}-2}}$ 

 f(x0 is defined when 

$[x]^{2}-[x]-2 >0$

$([x]-2)([x]+1)>0$

 [x] >2 and [x] <-1

 $x\geq 3$and x<-1

 $\therefore$   Domain of f(x)  is  x $\in$$(-\infty,-1)\cup (3, \infty)$