1)

If A+B+C =270°  , then

cos2A+cos2B+cos2C+4sinAsinBsinC=


A) 3

B) 2

C) 1

D) -1

Answer:

Option C

Explanation:

Given , A+B+C =270° 

and   cos2A+cos2B+cos2C+4sinAsinBsinC

 = 2cos(A+B)cos(AB)+12sin2C+4sinAsinBsinC

  =2cos(2700C)cos(AB)+12sin2C+4sinAsinBsinC

 = 12sinC[cos(AB)+sinC]+4sinAsinBsinC

 = 12sinC[cos(AB)+sinC]+4sinAsinBsinC

 =12sinC[cos(AB)cos(A+B)]+4sinAsinBsinC

 =14sinAsinBsinC+4sinAsinBsinC=1