1) sin2(30)+sin2(60)+sin2(90)+....+sin2(840)+sin2(870)+sin2(900)= A) 312 B) 392 C) 592 D) 36 Answer: Option AExplanation:We have, sin2(30)+sin2(60)+sin2(90)+....+sin2(840)+sin2(870)+sin2(900) =sin2(30)+sin2(870)+sin2(60)+sin2(840)+...........sin2(900)= =1+1+1+.... 15 times + (1√2)2=15+12=312