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1)

i2+i3+.......+i4000=


A) 1

B) 0

C) i

D) -i

Answer:

Option D

Explanation:

    in+in+1+in+2+in+3=0,nInteger

So, i2+i3+i4+.........+i4000

 = i+[i+i2+i3+.....+i4000]=-i