1) i2+i3+.......+i4000= A) 1 B) 0 C) i D) -i Answer: Option DExplanation:∵ in+in+1+in+2+in+3=0,∀n∈Integer So, i2+i3+i4+.........+i4000 = −i+[i+i2+i3+.....+i4000]=-i