1)

Calculate the depression in the freezing point of a solution  containing 0.1 g of K3[Fe(CN)6] in 100 g of H2O? (molecular  weight of  K3[Fe(CN)6] =369; Kf=1.86 K Kg mol-1)


A) 0

B) 1.223

C) 0.0226

D) 0.226

Answer:

Option C

Explanation:

Given,

Mass of  K3[Fe(CN)6] =0.1 g

 Mass of solvent =100 g

 Molar mass of K3[Fe(CN)6] =329 g mol-1 

kf =1.86 K kg/mol

K3[Fe(CN)6]3K++Fe(CN)6]

 i(van't Hoff factor)=3+1=4

 From, depression in freezing point,

Tf=i×Kf×m

 Tf=4×1.86Kkg/mol×0.1g329g×1000100kg

 Tf=0.0226K

Thus, option (c)  is correct