Answer:
Option C
Explanation:
Given,
Mass of K3[Fe(CN)6] =0.1 g
Mass of solvent =100 g
Molar mass of K3[Fe(CN)6] =329 g mol-1
kf =1.86 K kg/mol
K3[Fe(CN)6]⇌3K++Fe(CN)6]−
i(van't Hoff factor)=3+1=4
From, depression in freezing point,
Tf=i×Kf×m
Tf=4×1.86Kkg/mol×0.1g329g×1000100kg
Tf=0.0226K
Thus, option (c) is correct