Discussion Forum

 While combusting in air, 4g of $H_{2}$  gas was completely converted into water .If 36 $\mu$ mole of $CO_{2}$ from air is dissolved into that water, what is the concentration of $CO_{2}$?

Answer:

Explanation:

The equation takes place as follows;

 $2H_{2}+O_{2} \rightarrow   2H_{2}O$

  4g                            36g

 $\because$  36 g of $CO_{2}$ is dissolved  in 36 g of $H_{2}O$

$\therefore$   Conc. of $CO_{2}$= $\frac{36 \times 10^{-6} \times 10^{3}}{36}$

                                           $\left(\because conc:(C)=\frac{n}{v}\right)$

 = $10^{-3}$ M=1mM

 Hence , option (b) is the correct answer.