1)

Diffusion of CH4(g) and O2  (g) occurs under similar conditions, then the ratio of their rates of diffusion is 


A) 1.414

B) 0.707

C) 2.312

D) 1.732

Answer:

Option A

Explanation:

From Grahjam 's law of diffusion:

rCH4rO2=MO2MCH4

here, rCH4= rate of diffusion of CH4 gas

      rO2= rate of diffusion of O2 gas

MCH4= molecular mass of CH4=16

and   MO2 = molecular mass of O2 gas=32

Hence,   rCH4rO2=3216=2=1.414