Answer:
Option B
Explanation:
bond order= (Number of bonding electrons- Number of anti-bonding electrons)/ 2
Bond order of $N_{2}^{-}$ is $\frac{(10-5)}{2}= \frac{5}{2}$=2.5
Bond order of $NO^{-}$ is $\frac{(10-6)}{2}=\frac{4}{2}=2$
Bond order of $C_{2}^{-}$ is $\frac{1}{2} (9-4)=\frac{5}{2}$=2.5
Bond order of $N_{2}^{+}$ is $\frac{(9-4)}{2}=\frac{5}{2}$=2.5
Bond order of $C_{2}^{2-}$ is $\frac{(10-4)}{2}=\frac{6}{2}=3$
Bond order of $CN^{+}$ is $\frac{(8-4)}{2}=2$
