Discussion Forum

Statement   (A)  Sulphur vapour is paramagnetic

Statement (B) Reaction of dil.HCl with finely divided  iron forms $FeCl_{3}$ and $H_{2}$ gas

 The correct answer is 

Answer:

Explanation:

Statement (A)  Sulphur vapour is  paramagnetic is correct statement as sulphur vapour has formula $S_{2}$ , i.e, similar to $O_{2}$  and $O_{2}$ has two unpaired  electrons in its anti-bonding molecular orbitals

Statement (B)   Reaction of HCl (dil.) with finely divided iron forms $FeCl_{3}$ and $H_{2}$ gas  isa wrong  statement as the  whole reaction in as follows :

$Fe+2HCl(dil.)\rightarrow FeCl_{2}+H_{2}(g)$

 The $H_{2}$ (g)   produced will prevent the formation  of $Fe^{3+}$ (i.e, $FeCl_{3}$)

Hence, option (a)   is the correct answer