Discussion Forum

1)

For the reaction ,

$0.5 C(s)+0.5 CO_{2}(g)\rightleftharpoons CO(g)$

the equilibrium pressure is 12 atm . If CO₂ conversion is 50%  the value  of K_p, in atm is 

Answer:

Option A

Explanation:

 For the reaction,

$0.5 C(s)+0.5 CO_{2}(g)\rightleftharpoons CO(g)$

 $0.5 CO_{2}(g)$ can give CO(g) .

If 50% conversion  of $CO_{2}(g)$ takes place.

We have concentration  of $CO_{2}(g)$ = [0.25]

$\because$  K_p  is calculated only for gaseous  items,

thus

$K_{p}= \frac{[product]_{(g)}}{[Reactant]_{g}}= \frac{[1]}{[0.25]}=4$

 Hence, option (a) is the correct answer.