Physics | TS EAMCET 2018 | Discussion Page

In the diode-based rectifier circuit given below, If $V_{s}-V_{m}\sin \omega t$ and the diode is ideal, then the average value of $V_{L}$ is

$\frac{R_{L}}{(R_{L}+R_{S})}\frac{V_{m}}{\pi}$

$R_{L} V_{m} \sin \omega t$

$\frac{R_{L}}{(R_{L}+R_{S})}V_{m}$

$\frac{R_{L}}{(R_{L}+R_{S})}V_{m} \sin \omega t$

Option A

Given , AC voltage , $V_{s}=V_{m}\sin \omega t$

and $V_{m}$ = maximum value of voltage

In the given circuit diode will only conduct current in forward bias, so output across $R_{L}$ will be

Average Voltage , $V_{av}=\frac{V_{m}}{\pi}$

average current $I_{av}= \frac{V_{av}}{R}$

Total resistance , $R= R_{S}+R_{L}$

$I_{av}=\frac{V_{m}}{(R_{S}+R_{L})\pi}$

Now, voltage across $R_{L}$

$V_{L}=I_{av}.R_{L}$

$V_{L}$ = $\frac{R_{L}}{(R_{L}+R_{S})}\frac{V_{m}}{\pi}$

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