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1)

 If  A=[1101] and   I=[1001]  then for all  nN

 


A) An=nA

B) An=nA+(n1)A

C) An=(n1)Anl

D) An=nA(n1)l

Answer:

Option D

Explanation:

 We have

A=[1101] and   I=[1001]

 Now,     A2=A.A=  [1101][1101]=[1201]

 =2[1101][1101]=2A(21)I

Again,     A3=A2.A=  [1201][1101]=[1301]

 =3[1101]2[1001]=3A(31)I

      A=nA(n1)I