Answer:
Option D
Explanation:
Let n=4 be number of envelopes in which number letters goes into envelope meants for it
Then, the number of ways =4!= ∑4k=14Ck
[ ∵ required number of ways = n!= \sum_{k=1}^{n}{^{n}}{C}_{k}
=24-[^{4}C_{1}+^{4}C_{2}+^{4}C_{3}+^{4}C_{4}]
=24-[4+6+4+1]=24-15=9
Hence , required number of ways =9