1) xn+yn is divisible by A) x-y for all n∈N B) x+y for all n∈N C) x+y for all n=2m-1 , m∈N D) x+y for all n=2m, m∈N Answer: Option CExplanation:Given , xn+yn at n=1,x+y , which is divisible by x+y n=2, x2+y2, which is not divisble by x+y n=3, x3+y3 , which is divisble by x+y Hence, clearly xn+yn is divisble by n= odd numbers as n=2m-1 , where M∈N.
