Discussion Forum



1)

 In reaction  (1), $XeF_{6}$  hydrolysis  to form HF and X . In reaction (2), $XeF_{6}$  on partial hydrolysis form HF, Y and Z

 The products X, Y, Z respectively, are 


A) $ XeO_{3},Xe, XeO_{2}F_{2}$

B) $XeO_{3},XeOF_{4},XeO_{2}F_{2}$

C) $Xe, XeOF_{4},XeO_{2}F_{2}$

D) $XeO_{3},O_{2},Xe O_{2},F_{2}$

Answer:

Option B

Explanation:

 Complete hydrolysis of $XeF_{6}$ produces xenon trioxide

     $XeF_{6}+3H_{2}O \rightarrow   XeO_{3}+6HF$

whereas partial hydrolysis  of $XeF_{6}$  form different  products

   $XeF_{6}+2H_{2}O \rightarrow   XeO_{2}F_{2}+4HF$

  $XeF_{6}+H_{2}O \rightarrow   XeOF_{4}+2HF$