1)

 If equilibrium constant of a process is 3.8×103 at 250C  , standard free energy change of the process is 

 (R=8.314Jmol1K1,log0.0038=2.42)


A) 5.7kJmol1

B) 9.9kJmol1

C) 13.8kJmol1

D) 15.6kJmol1

Answer:

Option C

Explanation:

G0=RTlnK

G0=2.303RTlogK

G0=2.303×8.314mol1×298log3.8×103

G0=13.8×103Jmol1

G0=13.8kJmol1