Discussion Forum

The following plot represents the de-Broglie  wavelength as a function of the kinetic energy (K.E) of two particles A and B ,Identify the correct relation 

Answer:

Explanation:

 E=K.E         $hv=\frac{1}{2}mv^{2}$         $h \frac{c}{\lambda}=\frac{1}{2}mv^{2}$

 As increasing mass of particle

 slope of $\lambda$ vs $\sqrt{\frac{1}{K.E}}$ decreases.