1) The following plot represents the de-Broglie wavelength as a function of the kinetic energy (K.E) of two particles A and B ,Identify the correct relation A) $m_{A} =m_{B}$ B) $m_{A} \lt m_{B}$ C) $m_{A} \gt m_{B}$ D) $m_{A} =m_{B}$=0 Answer: Option CExplanation: E=K.E $hv=\frac{1}{2}mv^{2}$ $h \frac{c}{\lambda}=\frac{1}{2}mv^{2}$ As increasing mass of particle slope of $\lambda$ vs $\sqrt{\frac{1}{K.E}}$ decreases.
