Discussion Forum

Henry's law constant for $CO_{2}$ in water is 1.67 K bar at $25^{0}C$. The  quantity of $CO_{2}$  in 1000 mL of soda water  when packed under 5 bar $CO_{2}$ pressure at $25^{0} C$ is 

Answer:

Explanation:

We know that

$p= K_{B}\chi_{i}\Rightarrow p=K_{H}\times \frac{n_{1}}{n_{1}+n_{2}}$

 Given   is p= pressure (5 bar)

      $K_{H}$= Henery's  constant (1.67 K  bar)

$\chi_{1}$= mole fraction of solute   $CO_{2}$

 $\chi_{1}$= $\frac{n_{1}}{n_{1}+n_{2}} \Rightarrow =5=1.67 \times 10^{3} \times \frac{ H_{1}}{55.5}$

  $H_{1}= \frac{55.5 \times 5}{1.67 \times 10^{3}}=0.167 mol$