1) What are X and Y , respectively in the following reactions? $Au+aqua-regia\rightarrow AuCl_{4}^{-}+H_{2}O+X$ $Pt+aqua-regia\rightarrow PtCl_{6}^{2-}+H_{2}O+Y$ A) $N_{2}O, NO$ B) $N_{2}O,N_{2}O$ C) $NO,NO$ D) $NO, NO_{2}$ Answer: Option CExplanation:$3Au+HNO_{3}+3HCl\rightleftharpoons 3AuCl+NO+H_{2}O$ (aqua-regia) (x) $3Pt+4HNO_{3}+12HCl\rightleftharpoons 3PtCl_{4}+4NO+8H_{2}O$ (aqua-regia) (Y)
