Discussion Forum

A litre of sea water (which weights 1030 g) contains $6 \times 10^{-3}$ g of dissolved oxygen. The concentration of dissolved oxygen in ppm is 

Answer:

Explanation:

 Parts per million

  = (Number of parts of component / Total number of parts of all  Components of the solution )x 10⁶

Here,  Number of parts of component= amount of  dissolved oxygen = $6 \times 10^{-3}$ g

 Total number of parts of all components of the solution=  amount of sea water =1030 g

 $\therefore$   Concentration of dissolved  oxygen in ppm

  = $\frac{6 \times 10^{-3}}{1030} \times 10^{6}= \frac{6}{1030} \times 10^{3}$

 = $0.005825 \times 10^{3}$ ppm

 =5.8 ppm