1) A particle of mass M is moving in a horizontal circle of radius R with uniform speed v. When the particle moves from one point to a diametrically opposite point, its A) momentum does not change B) momentum changes by 2Mv C) kinetic energy changes by $\frac{Mv^{2}}{4}$ D) Kinetic energy changes by $Mv^{2}$ Answer: Option BExplanation:Given, Velocity of particle =v Change in momentum = final momentum-initial momentum= Mv-(-Mv)=2Mv
