Discussion Forum

An AC generator 10V (rms)  at 200 rad/s is connected in series with a $50 \Omega$ resistor, a  400 mH inductor and a $200 \mu F$ capacitor. The rms voltage  across the inductor is 

Answer:

Explanation:

 Given, E= 10 V

     $\omega$= 200 rad/s

  R= 50 $\Omega$

L=400 mH

 C=200 $\mu$ F

 We know that,

    $Z=\sqrt{R^{2}+(X_{L}-X_{c})^{2}}$

     $Z=\sqrt{(50)^{2}+(80-25)^{2}}=\sqrt{(50)^{2}-(55)^{2}}$

$=\sqrt{2500+3025}$

 Z= $\sqrt{5525}=74.3 \Omega$

  $I= \frac{E}{Z}=\frac{10}{74.3}=0.13459 A$

 $E_{L}=IX_{L}=0.13459 \times 80$

  =10.76 V or 10.8 V