Discussion Forum

 A meter scale made of steel , reads accurately at $25^{0}$ C.  Suppose  in an experiment an accuracy of 0.06 mm in 1 m is required, the range of temperature in which the experiment can be performed with this meter scale  is (coefficient of linear expansion of steel is $11 \times 10^{-6} /° C)$

Answer:

Explanation:

 Given , coefficient of linear  expansion  of steel,

  $\alpha = 11 \times 10^{-6}  / ^{0} C$

 We know that,

 $\triangle l= l \alpha \triangle t \Rightarrow \triangle t = \frac{ \triangle l}{ l \alpha}$

 Here, $\triangle l= 6 \times 10^{-5} m \Rightarrow l=1m$

 $\triangle t= \frac{ 6 \times 10^{-5}}{1 \times 11 \times 10^{-6}}$

              =$5.45^{0} C$

 So, the range of temperature in which the experiment  can be hence performed him this  metre scale will be $19^{0}C to 31^{0}C$

 Here, option (a) is correct