Answer:
Option B
Explanation:
The net charge on upper plates both the capacitor $(2 \mu F$ and $3\mu F)$ will be $+80 \mu C$ . So charge on upper plate of
$3 \mu C$ capacitor will be
$q=\left(\frac{3}{3+2}\right)(80\mu C)$
$ q= \frac{3}{5} \times 80$= $48 \mu C$