1) If A and B are events having probabilities P(A)=0.6 , P(B)=0.4 and P(A∩B)=0 , then probability that neither A nor B occurs is A) 14 B) 1 C) 12 D) 0 Answer: Option DExplanation:Given, P(A)=0.6 , P(B)=0.4 and P(A∩B)=0 then P(neither A nor B)= P(¯A∩¯B) = P(¯A∩B)=1−P(A∪B) = 1−P(A)−P(B)+P(A∩B) [∵P(A∪B)=P(A)+P(B)−P(A∩B)] =1-0.6-0.4+0=1-1=0