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1)

If A and B are events having probabilities P(A)=0.6 , P(B)=0.4  and  P(AB)=0 , then probability that neither  A nor B occurs is 


A) 14

B) 1

C) 12

D) 0

Answer:

Option D

Explanation:

Given, P(A)=0.6 , P(B)=0.4 and P(AB)=0  then

P(neither A nor B)= P(¯A¯B)

= P(¯AB)=1P(AB)

    = 1P(A)P(B)+P(AB)

              [P(AB)=P(A)+P(B)P(AB)]

  =1-0.6-0.4+0=1-1=0