Mathematics | TS EAMCET 2017 | Discussion Page

An integer is chosen from $\left\{2k/-9\leq k\leq10\right\}$ .The probability that it is divisible by both 4 and 6 is

$\frac{1}{10}$

$\frac{1}{20}$

$\frac{1}{4}$

$\frac{3}{20}$

Option D

Let S= $\left\{2k/-9\leq k\leq10\right\}$ =

{-18,-16,-14,.......,0,2,4,6,....20}

Total number of possible outcomes =20

Favourable outcomes are -12,0 and 12

So, number of favourable outcomes =3

$\therefore$ Required probability= $\frac{3}{20}$

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