Discussion Forum



1)

An integer is chosen from $\left\{2k/-9\leq k\leq10\right\}$   .The probability that it is divisible  by both 4 and 6 is 


A) $\frac{1}{10}$

B) $\frac{1}{20}$

C) $\frac{1}{4}$

D) $\frac{3}{20}$

Answer:

Option D

Explanation:

Let S=$\left\{2k/-9\leq k\leq10\right\}$ =

 {-18,-16,-14,.......,0,2,4,6,....20}

 Total number of possible outcomes =20

  Favourable  outcomes are -12,0 and 12

 So, number of favourable outcomes =3

  $\therefore$   Required probability= $\frac{3}{20}$