1)

If =[156017001]

and =[10130346100]


A) \triangle^{2}-3\triangle'=0

B) (\triangle+\triangle')^{2}-3(\triangle+\triangle')+2=0

C) (\triangle+\triangle')^{2}-3(\triangle+\triangle')+5=0

D) \triangle+3\triangle'+1

Answer:

Option B

Explanation:

Given, 

=[156017001]

     = 1(10)5(00)+6(00)

   =10+0

=1

 If =1 and =[10130346100]

             =1(018)0(30012)+1(180)

=180+18

    =0

  Now, (+)23(+)+2

 =(1+0)23(1+0)+2

  =-2+2=0