Discussion Forum

The product of all the real roots  of  $x^{2}-8x+9-\frac{8}{x}+\frac{1}{x^{2}}=0$ is 

Answer:

Explanation:

We have 

$x^{2}-8x+9-\frac{8}{x}+\frac{1}{x^{2}}=0$

 $\Rightarrow$      $x^{4}-8x^{3}+9x^{2}-8x+1=0$

Product of roots =1