Answer:
Option C
Explanation:
We have,
$\sum P_{i}=a+a+a+b+b+b+0.3$
$\Rightarrow$ $1=3a+2b+0.3$
$\Rightarrow$ $3a+2b=0.7$ .........(i)
$\sum P_{i}x_{i}=a+2a+3a+4b+5b+1.8$
$\Rightarrow$ $4.2=6a+9b+1.8$
$\Rightarrow$ $2a+3b=0.8$ .........(ii)
Solving Eqs,(i) and (ii), we get
a=0.1, b=0.2