Answer:
Option B
Explanation:
Equation of plane passes through the points (1,-1,6) ,(0,0,7) and perpendicular to the plane x-2y+z=6 is
$\begin{bmatrix}x-1 & y+1&z-6 \\0-1 & 0+1&7-6\\1&-2&1 \end{bmatrix}=0$
$\Rightarrow$ $\begin{bmatrix}x-1 & y+1&z-6 \\-1 & 1&1\\1&-2&1 \end{bmatrix}=0$
$\Rightarrow$ $(x-1)(1+2)-(y+1)(-1-1)+(z-6)(2-1)=0$
$\Rightarrow$ $3x-3+2y+2+z-6=0$
$\Rightarrow$ $3x+2y+z-7=0$
This plane is passes through (1,1,2)
