1)

$\lim_{y \rightarrow1}\left(\frac{1}{y^{2}-1}-\frac{2}{y^{4}-1}\right)=$


A) $\frac{1}{2}$

B) $\frac{1}{3}$

C) $\frac{1}{4}$

D) 0

Answer:

Option A

Explanation:

 We have,

$\lim_{y \rightarrow1}\left(\frac{1}{y^{2}-1}-\frac{2}{y^{4}-1}\right)=$

 $=\lim_{y \rightarrow 1}\left(\frac{y^{2}+1-2}{y^{4}-1}\right)$ 

$=\lim_{y \rightarrow 1}\left(\frac{y^{2}-1}{(y^{2}-1)(y^{2}+1)}\right)$

  $=\lim_{y \rightarrow 1}\frac{1}{y^{2}+1}=\frac{1}{1+1}=\frac{1}{2}$