Mathematics | TS EAMCET 2017 | Discussion Page

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If the conjugate of $(x+iy)(1-2i)$ is (1+i) , then

$x+iy=1-i$

$x+iy=\frac{1-i}{1-2i}$

$x-iy=\frac{1-i}{1+2i}$

$x-iy=\frac{1-i}{1+i}$

Option B

We have ,

Conjugate of (x+iy)(1-2i) is 1+i

i.e, (x-iy)(1+2i)=1+i

$\Rightarrow$ $x-iy= \frac{1+i}{1+2i}$

Taking conjugate both sides , we get

$x+iy=\frac{1-i}{1-2i}$

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