1) If the conjugate of (x+iy)(1−2i) is (1+i) , then A) x+iy=1−i B) x+iy=1−i1−2i C) x−iy=1−i1+2i D) x−iy=1−i1+i Answer: Option BExplanation:We have , Conjugate of (x+iy)(1-2i) is 1+i i.e, (x-iy)(1+2i)=1+i ⇒ x−iy=1+i1+2i Taking conjugate both sides , we get x+iy=1−i1−2i