Mathematics | TS EAMCET 2017 | Discussion Page

The bad contains 5 red balls, 3 black balls and 4 white balls . Three balls are drawn at random . The probability that they are not of same colour is

$\frac{37}{44}$

$\frac{31}{44}$

$\frac{21}{44}$

$\frac{41}{44}$

Option D

We have,

5 red balls, 3 black balls , 4 white balls

Total number of balls =(5+3+4)=12

Three balls are drawn= $^{12}C_{3}=220$

Three balls are drawn of same colour

$^{5}C_{3}+^{3}C_{3}+^{4}C_{3}=10+1+4=15$

Probability of are not same colour

=1- Probability of same colour

= $1-\frac{15}{220}=1- \frac{3}{44}=\frac{41}{44}$

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