1) If A=[1010201−14], A=B+C, B=BT and C=−CT , then C= A) [00.50−0.500000] B) [000000.50−0.50] C) [0−0.50.50.50−0.500] D) [00.50.5−0.500.50−0.50] Answer: Option BExplanation:We have, A=[1010201−14] AT=[10102−1104] A+AT=[20204−12−18], A−AT=[0000010−10] A=12(A+AT)+12(A−AT) A=[10102−0.51−0.54]+[000000.50−0.50] A= B+C C=[000000.50−0.50]= −CT